1.

The limiting molar conductivities of HCl, CH_(3)COONa and NaCl are respectively 425, 90 and 250 mho cm^(2)mol^(-1) at 25^(@)C.t he molar conductivity of 0.1 M CH_(3)COOH solution is 7.8 mho cm^(2)mol^(-1) at the same temperature. The degree of dissociation of 0.1 M acetic acid solution at the same temperature is

Answer»

`0.10`
`0.02`
`0.15`
`0.03`

SOLUTION :`wedge_(CH_(3)COOH)^(@)=wedge_(CH_(3)COONa)^(@)+wedge_(HCL)^(@)-wedge_(NaCl)^(@)`
`=90+425-125=390" MHO "cm^(2)mol^(-1)`
`alpha=(wedge_(m)^(@))/(wedge_(m)^(@))=(7.8)/(390)=.02`


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