

InterviewSolution
Saved Bookmarks
1. |
The line L given by `x/5+y/b=1`passes through the point (13,32). The line K is parallel to L and has the equation `x/c+y/3=1`Then the distance between L andK is(1) `sqrt(17)`(2) `(17)/(sqrt(15))`(3) `(23)/(sqrt(17))`(4) `(23)/(sqrt(15))` |
Answer» `K || L` `L: x/5 + y/b = 1` `L(13,32) = 13/5 + 32/b = 1` `32/b = 1- 13/5` `32/b = -8/5` `b= -32 xx5/8 = -20` `x/5 - y/20 = 1` `y = 20 x/5 -20 =4x - 20` slope of L=`4` slope of K=`4` `x/c + y/3 = 1` `y = -x/c 3 + 3` `=> -3/c = 4` `c= -3/4` k: `y= 4x + 3` distance= `|(c_1 - c_2)/(sqrt(a^2 + b^2))| = |(-20-3)/(sqrt(1+16))|` `= 23/sqrt17` answer |
|