1.

The line L given by `x/5+y/b=1`passes through the point (13,32). The line K is parallel to L and has the equation `x/c+y/3=1`Then the distance between L andK is(1) `sqrt(17)`(2) `(17)/(sqrt(15))`(3) `(23)/(sqrt(17))`(4) `(23)/(sqrt(15))`

Answer» `K || L`
`L: x/5 + y/b = 1`
`L(13,32) = 13/5 + 32/b = 1`
`32/b = 1- 13/5`
`32/b = -8/5`
`b= -32 xx5/8 = -20`
`x/5 - y/20 = 1`
`y = 20 x/5 -20 =4x - 20`
slope of L=`4`
slope of K=`4`
`x/c + y/3 = 1`
`y = -x/c 3 + 3`
`=> -3/c = 4`
`c= -3/4`
k: `y= 4x + 3`
distance= `|(c_1 - c_2)/(sqrt(a^2 + b^2))| = |(-20-3)/(sqrt(1+16))|`
`= 23/sqrt17`
answer


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