The line x+2y+3=0 cuts the circle x2+y2+4x+4y−1=0 at points P and Q – InterviewSolution

1.	The line x+2y+3=0 cuts the circle x2+y2+4x+4y−1=0 at points P and Q and the line 2x+3y+λ=0 cuts the circle x2+y2+6x+2y−7=0 at points R and S. If P, Q, R and S are concyclic, then the value of λ is
Answer» The line $x + 2 y + 3 = 0$ cuts the circle $x^{2} + y^{2} + 4 x + 4 y - 1 = 0$ at points $P$ and $Q$ and the line $2 x + 3 y + λ = 0$ cuts the circle $x^{2} + y^{2} + 6 x + 2 y - 7 = 0$ at points $R$ and $S .$ If $P,$ $Q,$ $R$ and $S$ are concyclic, then the value of $λ$ is

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