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The line `y=0` divides the line joining the points (3, -5) and (-4, 7) in the ratio :A. `3 : 4`B. `4 : 5`C. `5 : 7`D. `7 : 9` |
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Answer» Correct Answer - C Let P( x, y) be the point of division that divides the line joining (3, -5) and (-4, 7) in the ratio of `k:1` Now, `y=(7k-5)/(k+1)` ...(i) Since, P lies on `y=0` or x-axis then, from eq. (i) `0=(7k-5)/(k+1) implies 7k=5 implies k=5/7` |
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