1.

The linear density of a vibrating string is `10^(-4) kg//m`. A transverse wave is propagating on the string, which is described by the equation `y=0.02 sin (x+30t)`, where x and y are in metres and time t in seconds. Then tension in the string isA. 0.09 NB. 0.36 NC. 0.9 ND. 3.6 N

Answer» Correct Answer - a
`y=0.02 sin (x+30t)`
comparing with standard equation
`y=A sin (Kx+omegat),omega=30, K=1`
velocity of wave,
`v=(omega)/(K)=(30)/(1)=30 m//s`
Expression `v=sqrt((T)/(m))` gives
Tension `T=v^(2)m=(30)^(2)xx10^(-4)`
`=0.09 N`


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