InterviewSolution
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InterviewSolution
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The lines `x + y=|a| and ax-y = 1` intersect each other in the first quadrant. Then the set of all possible values of a is the interval:A. `[1,oo)`B. `(-1,oo)`C. `(-1,1)`D. `(0,oo)` |
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Answer» Correct Answer - A Given lines intersect at the point `P((1+|a|)/(1+a),(a|a|-1)/(1+a))` This point will lie in first quadrant iff `1+a gt0 and a|a| -1 gt 0` `implies a gt -1 and a|a| -1 ge 0` `implies a^(2)-1 ge 0 " if " a ge 0 " or " , -a^(2)-1 gt 0 " if " 0 lt a lt -1` `implies a in [1,oo)` |
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