InterviewSolution
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InterviewSolution
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The load current in the transmitting antenna of an unmodulated AM transmitter is 6 Amp. What will be the antenna current when modulation is 60%. |
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Answer» Solution :Total power carried by AM wave `P_(T)=P_(C)(1+(m^(2))/(2))`…..(1) Where `P_(C)` is the power of carrier componenet and m is the modulation factor.If R is the resistance ,`I_(m)` the antenna LOAD current when modulation is 60% and `I_(C)` Is the antenna load current when unmodulated ,then `(P_(T))/(P_(C))=(I_(m)^(2)R)/(I_(C)^(2)R)""therefore 1+(m^(2))/(2)=(I_(m)^(2))/(I_(C)^(2))` USING (1) or `I_(m)=I_(C)SQRT({(1+(m^(2))/(2))})` Given `I_(C)`=6Amp,m=0.6 6[1.086]=6.52 Amp. |
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