1.

The log - log graph between the energy `E` of an electron and its de - Broglie wavelength `lambda` will beA. B. C. D.

Answer» Correct Answer - C
`l = (h)/(sqrt( 2 m E)) = (1)/(sqrt(2 m E)) . (1)/(sqrt ( E))`. Taking log of both sides
`log lambda = log (1)/(sqrt (2 m)) + log (1)/( sqrt (E ))`
`rArr log lambda = log (h)/(sqrt ( 2m)) - (1)/(2) log E`
`rArr log lambda = -(1)/(2) log E + log (h)/(sqrt( 2 m))`
This is the equation of straight line having slope `( - 1//2)` and positive intercept on `log lambda` axis.


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