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The longest wavelength that the singly ionized helium atom in its ground state will obsorb isA. `912 Å`B. `304 Å`C. `606 Å`D. `1216 Å` |
Answer» Correct Answer - B `lambda = (912 Å)/(Z^(2) [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]` for singly ionized helium atom `Z = 2` for the wavelength to be longest, `n_(1) = 1, n_(2) = 2` `:. lambda = (912 Å)/((2^(2))[1 - (1)/(4)]) = (912)/(3) = 304 Å` |
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