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The loop ABCD is moving with velocity .v. towards right. The magnetic field is 4 T. The loop is connected to a resistance of 8 ohm. If steady current of 2 A flows in the loop then value of u if loop has a resistance of 4 ohm, is : (Given AB=30 cm, AD=30 cm) |
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Answer» Solution :The induced emf in the loop is e = Blv ` e = B(AD) sin 37^@ v - 4 xx 0.3 sin 37^@ v` Effective RESISTANCE of the circuit is R = (4+8)= 12 ohm Hence i` = e/R = (Blv)/( R)` ` rArr 2 = (4 xx 0.3 xx sin 37^@ mu)/((4+8))` ` therefore v = 100/3 m//s ` |
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