1.

The m olality of solution is 10m and molar mass of solvent is 100 g "mol"^(-1) then mole fraction of solute will be

Answer»

0.5
5
0.005
0.05

Solution :`X_(2) = (mM_(1))/(1000+mM_(1))`
`(10 XX 100)/(1000 + 10 xx 100)=1000/2000= 0.5`


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