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The magnetic field at the centre of ring carrying electric current is ____ of area of the ring. |
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Answer» inversely proportional to square ROOT But `A=pia^(2)` `thereforea=(A/pi)^(1/2)` `thereforeB=(mu_(0)Ixxpi^(1/2))/(2xxA^(1/2))` `thereforeBprop1/A^(1/2)" "[because"Other TERMS are constant"]` |
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