1.

The magnetic field at the centre of ring carrying electric current is ____ of area of the ring.

Answer»

inversely proportional to square ROOT
inversely proportional
directly proportional
directly proportional to square root

Solution :`B=(mu_(0)I)/(2a)`
But `A=pia^(2)`
`thereforea=(A/pi)^(1/2)`
`thereforeB=(mu_(0)Ixxpi^(1/2))/(2xxA^(1/2))`
`thereforeBprop1/A^(1/2)" "[because"Other TERMS are constant"]`


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