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The magnetic field in a plane electromagnetic wave is given by B_(y)=(2xx10^(-7)) T sin (0.5xx10^(3)x+1.5xx10^(11)t). What is the wavelength and frequency of the wave? |
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Answer» Solution :COMPARING the given equation with `B_(y) = B_(o) SIN [2 pi ((x)/(lamda)+(t)/(T))]` We get, `lamda =(2 pi)/(0.5xx10^(3)) m=1.26 cm, and (1)/(T) =v= (1.5xx10^(11))//2pi =23.9 GHz` |
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