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The magnetic field in a plane electromagnetic wave is given byB_(y)=2xx10^(-7)sin (0.5xx10^(3)x + 1.5 xx 10^(11) t)T. What is the wavelength and frequency of the wave ? |
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Answer» Solution :a) Comparing the given equation with `B_(y)=B_(0)sin[2pi[((x)/(lambda)+(t)/(T))]` we get, `lambda=(2pi)/(0.5xx10^(3))m=1.26cm` and `(1)/(T)=v=(1.5xx10^(11))//2pi=23.9GHz` b) `E_(0)=B_(0)c=2xx10^(-7)Txx3xx10^(8)m//s=6xx10^(1)V//m` The electric field component is perpendicular to the direction of PROPAGATION and the direction of magnetic field. THEREFORE, the electric field component along the z-axis is obtained as `E_(z)=60sin(0.5xx10^(3)x+1.5xx10^(11)t)V//m` |
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