Saved Bookmarks
| 1. |
The magnetic field in a plane electromagnetic wave is given byB_(y)=2xx10^(-7)sin(0.5xx10^(3)x +1.5xx10^(11)t)T.a.What is the wavelength and frequency of the wave ?b.Write an expression for the electric field. |
|
Answer» Solution :a.Comparing the given EQUATION with `B_(y)=B_(0)sin [2x((x)/(lambda)+(t)/(T))]`, we get,`lambda = (2pi)/(0.5xx10^(3))m=1.26cm`and`(1)/(T)=upsilon =((1.5xx10^(11)))/(2pi)=23.9` GHz. b.`E_(0)=B_(0)c=2xx10^(-7)xx3xx10^(8)=6xx10^(1)V//m` The electric field COMPONENT is perpendicular to the direction of propagation and the direction of magnetic field. Therefore, the electric field component along the z-axis is obtained as,`E_(z)=60 sin (0.5xx10^(3)x +1.5xx10^(11)t)V//m`. |
|