The magnetic field perpendicular to the plane of a conducting ring of radius r change ate the rate (dB)/(dt)

The magnetic field perpendicular to the plane of a conducting ring of

1.	The magnetic field perpendicular to the plane of a conducting ring of radius r change ate the rate (dB)/(dt)
Answer» The EMF induced in the RING is `pir^(2)(dB)/(dt)` The emf induced in the rintg is `2pir(dB)/(dt)` The potential difference between diametrically OPPOSITE POINTS on the ring is half of the induced emf. All points on the ring are at the same potential. Answer :A::D

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The magnetic field perpendicular to the plane of a conducting ring of radius r change ate the rate (dB)/(dt)

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