1.

The magnetic flux across a loop of resistance 10 Omega is given by phi = 5t^(2)-4t+1 weber. How much current is induced in the loop after 0.2 sec ?

Answer»

0.4 A
0.2 A
0.4 A
0.02 A

SOLUTION :MAGNETIC flux, `phi=5t^(2)-4t+1 Wb`
`therefore (d phi)/(dt)=10 t - 4 Wb s^(-1)`
The INDUCED emf is `epsilon =-(d phi)/(dt)=-(10 t - 4)`
At `t=0.2s, epsilon =- (10xx0.2-4)=2V`
The induced CURRENT is `I=(epsilon)/(R )=(2V)/(10 OMEGA)=0.2 A`


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