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The magnetic flux in a closed circuit of resistance 20ohm, varies with time (t) according to equation phi =8t^2-6t+5. What is the magnitude of induced current at time t = 1 sec? |
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Answer» SOLUTION :`E =(dphi)/DT` = d(8t^2-6t+5)/dt` `THEREFORE e = 16t-6 = 16xx1-6 = 10V` `therefore I = e/R = 10/20 = 0.5V` |
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