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The magnetic flux linked with a coil given by phi = 5t^2+3t+2 What is the e.m.f. induced in the coil in the third second? |
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Answer» Solution :`e = (dphi)/dt = d/dt(5t^2+3t+2) = 10t+3` When t = 2 SEC, `e_1` = 20+3 = 23V When t = 3 sec, `e_2` = 10+3 = 33 `THEREFORE` e.m.f. induced in the THIRD SECOND = 33-23 = 10V |
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