1.

The magnetic flux linked with a coil satisfies the relation phi=4t^(2)+6t+9 Wb, where t is the time in second. The em.f. induced in the coil at t = 2 second is

Answer»

22 V
18 V
16 V
40 V

Solution :Given : `PHI = 4t^(2)+6t+9 Wb`
`therefore` Induced e.m.f. `|EPSILON|=(d phi)/(DT)=(d)/(dt)(4t^(2)+6t+9)=8t+6 V`
At `t=2 s, |epsilon|=8xx2+6 V= 22V`


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