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The magnetic flux through a coil perpendicular to its plane is varying according to the relation phi_(B)= (5t^(3) + 4t^(2) + 2t -5) weber. Calculate the induced current through the coil at 1= 2 second. The resistance of the coil is 5 Omega |
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Answer» Solution :`phi= 5t^(3) + 4t^(2) + 2t-5` `|e| = (d phi)/(DT) = 15T^(2) + 8t + 2` `iR = 15t^(2) + 8t + 2` `i xx 5 = 15 xx 4 + 8 xx 2 + 2 RARR i= 15.6A` |
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