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The magnetic flux through a coil perpendicular to its plane is varying according to the relation phi_B = (5t^3+4t^2 +2t-5)weber. Calculate the induced current through the coil at t = 2 second. The resistance of the coil is 5Omega |
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Answer» SOLUTION :`phi = 5t^3 + 4t^2 + 2t - 5` `|e| = (dphi)/(dt) = 15t^2 + 8t + 2` at, t = 2sec, e= -78 V`e = IR = 15t^2 + 8t + 2` `I xx 5 = 15 xx 4 + 8 xx 2 + 2 RARR I = 15.6 A` |
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