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InterviewSolution
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The magnetic flux through a coil perpendicular to its plane is varying according to the relation phi_(B)= (5t^(3) +4t^(2) + 2t - 5) weber. Calculate the induced current through the coil at t = 2 second. The resistance of the coil is 5 Omega. |
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Answer» Solution :`phi=5t^(3)+4t^(2)+2t-5 IMPLIES |E| =(d phi)/(DT)=15t^(2)+8t+2` at t=2sec, e = -78V `implies e=iR=15t^(2)+8t+2` `I xx 5=15 xx 4+8 xx 2 implies i=15.6A` |
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