1.

The magnetic induction at O due to a current in conductor shaped as shown in figure

Answer»

`(mu_(0)i)/(4pi)[(3PI)/(2a)+(sqrt(2))/(B)]`
`(mu_(0)i)/(4pi)[(3pi)/(4a)-(sqrt(2))/(b)]`
`(mu_(0)i)/(4pi)[(3pi)/(4a)+(1)/(sqrt(2)b)]`
`(mu_(0)i)/(4pi)[(1)/(a)+(1)/(b)]`

Solution :`B_(1)=(mu_(0)iphi)/(4pia),B_(2)=(mu_(0)i)/(4pib)(sin0^(@)+sin45^(@))`
`:. B=B_(1)+B_(2)`


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