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InterviewSolution
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The magnetic moment of a bar magnet is 45 Am^(2) and its length is 10 cm. Calculate the magnetic field induction at a point 10 cm away from the centre of the magnet on the axial line. |
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Answer» Solution :Length of the magnet , 2l = 10 cm `= 10 xx 10^(-2)` m `implies l =5 xx 10^(-2) m` Distance of the POINT on axial line , d=10 cm `= 10 xx 10^(-2) m ` Magnetic moment, `M=45 Am^(2)` `:.` Magnetic induction on the axial line of the BAR magnet is `B = (mu_0)/( 4 PI ) (2MD)/((d^(2)-l^(2))^(2))` `B = (4 pi xx 10^(-7))/(4 pi) ( 2 xx 45 xx 10 xx 10^(-2))/([(10 xx 10^(-2))^(2) - ( 5 xx 10^(-2))^(2)]^(2))` ` = 16 xx 10^(-3) T ` |
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