InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The magnetic moment of a bar magnet is 45 Am^(2) and its length is 10 cm. Calculate the magnetic field induction at a point 10 cm away from the centre of the magnet on the axial line. |
| Answer» <html><body><p></p>Solution :Length of the magnet , 2l = 10 cm `= 10 xx 10^(-2)` m <br/> `implies l =5 xx 10^(-2) m` <br/> Distance of the <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> on axial line , d=10 cm <br/> `= 10 xx 10^(-2) m ` <br/> Magnetic moment, `M=<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a> Am^(2)` <br/> `:.` Magnetic induction on the axial line of the <a href="https://interviewquestions.tuteehub.com/tag/bar-892478" style="font-weight:bold;" target="_blank" title="Click to know more about BAR">BAR</a> magnet is `B = (mu_0)/( 4 <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> ) (2MD)/((d^(2)-l^(2))^(2))` <br/> `B = (4 pi xx 10^(-7))/(4 pi) ( 2 xx 45 xx 10 xx 10^(-2))/([(10 xx 10^(-2))^(2) - ( 5 xx 10^(-2))^(2)]^(2))` <br/> ` = 16 xx 10^(-3) T `</body></html> | |