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The magnetic moment of a bar magnet of length 20cm is 3.6 xx 10^(-6)A-m^(2). The magnetic length is 90% of its geometric length. Then find the pole strength of the magnet. |
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Answer» SOLUTION :Magnetic moment of the bar magnet ,`M=3.6 xx 10^(-6) A-m^(2)` Given that magnetic LENGTH is 90% of its geometric length . `:.` Magnet length ,`2l = (90)/(100) xx 20 =18 cm` Pole strength of the magnet `m=(M)/(2l) = (3.6 xx 10^(-6))/(18xx10^(-2)) = 2 xx 10^(-5) A-m` |
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