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The magnetic moment of a short bar magnet placed with its magnetic axis at `30^(@)` to an external field of 900 G and experiences a torque of 0.02 N m isA. `0.35Am^(2)`B. `0.44Am^(2)`C. `2.45Am^(2)`D. `1.5Am^(2)` |
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Answer» Correct Answer - B Here, B=900, Gauss=`900xx10^(-4)T` `=9xx10^(2)T` `tau=0.02Nm and theta=30^(@)` `Rightarrow 0.02=9xx10^(-2)xx(1)/(2)xxm` `m=(0.02xx2)/(9xx10^(-2))=0.44Am^(2)` |
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