1.

The magnetic potential at a point distant 10 cm from the middle point of a magnetic dipole on a line inclined at an angle of60^(@) with the axis is 3 e.m.u Then the magnetic moment of magnet is

Answer»

600 ab amp`cm^(2)`
300 ab amp `cm^(2)`
150 ab amp`cm^(2)`
300 `sqrt(3)` ab amo `cm^(2)`

Solution :`V=(mu_(0))/(4PI)(Mcostheta)/(r^(2))`
`V=(mcostheta)/(r^(2)) "in" C.G.S. system`
`M=(VR^(2))/(costheta)=(3xx100)/(cos60)=600 abA cm^(2)`


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