1.

The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance.

Answer»

13.89 H
0.138 H
1.389 H
138.88 H

SOLUTION :P.E=`1/2 LI^2`
`therefore L=(2xxP.E)/I^2`
`=(2xx25xx10^(-3))/(60xx10^(-3))^2`
`=(50xx10^3)/3600`
`=0.013888xx10^3` H
`therefore L approx` 13.89 H


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