1.

The magnetic susceptibility of a paramagnetic material at is 0.0075 and its value at will be

Answer»

0.0075
0.015
`0.0030`
0.0045

Solution :`(chi_(2))/(chi_(1))= (T_(1))/(T_(2)) RARR (chi_(2))/(0.0075)= (200)/(100) chi_(2)= 0.015`


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