1.

The magnitude of average accleration in half time period in a simple harmonic motion isA. `(2Aomega^(2))/(pi)`B. `(Aomega^(2))/(2pi)`C. `(Aomega^(2))/(sqrt(2)pi)`D. zero

Answer» Correct Answer - A
`lt` acceleration `gt = (int_(0)^(T//2)omega^(2)asinomegatdt)/(int_(0)^(T//2)dt) = (2piomega^(2))/(pi)`


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