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The magnitude of electric field intensity E is such that, an electron placed in it would experience an electrical force equal to its weight is given byA. `m"ge"`B. `(mg)/e`C. `e/(mg)`D. `(e^(2))/(m^(2))g` |
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Answer» (b) Force on electron `|F|=qE=eE=mgimpliesE=(mg)/e` |
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