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InterviewSolution
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The magnitude of gravitational potential energy of a body at a distance `r` from the centre of earth is u. Its weight at a distance 2r from the centre of earth isA. `(u)/(r)`B. `(u)/(4r)`C. `(u)/(2r)`D. `(4r)/(u)` |
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Answer» Correct Answer - B Potential energy `u=(GMm)/(r)` At distance `2r,(GM)/((2r)^(2))=(GM)/(4r^(2))=(u)/(4mr^(2))` Now, `W=mE=(u)/(4r)` |
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