1.

The magnitude of point charge due to which the electric field 30 c away has the magnitude2"N C"^(-1) will be

Answer»

`2xx10^(-11)C`
`3xx10^(-11)C`
`5xx10^(-11)C`
`9xx10^(-11)C`

Solution :`E=(KQ)/R^(2)`
`Q=(Er^(2))/K=(2xx(0.3)^(2))/(9xx10^(9))`
= `(2xx9xx10^(-2)xx10^(-9))/9`
`thereforeq=2xx10^(-11)C`


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