1.

The magnitude of spin angular momentum of an electron is given by

Answer»

`s=sqrt(s(s+1))`
`s=sxxh/(2pi)`
`s=(sqrt(3))/2xxh/(2pi)`
`s=+-1/2xxh/(2pi)`

SOLUTION :SPIN angularmomentum `=sqrt(s(s+1))H/(2pi)`
ALSO `s=sqrt(1/2(1/2+1))xxh/(2pi)=(sqrt(3))/2xxh/(2pi)`


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