The magnitude of the equatorial magnetic field due to a bar magnet of length 2 cm at a distance of 1lm from its mid-point is (magnetic moment of the bar magnet is 0.60 A m)A. `5.0xx10^(-5)` TB. `6.0xx10^(-8)` TC. `7.0xx10^(-7)` TD. `8.0xx10^(-8)` T

The magnitude of the equatorial magnetic field due to a bar magnet of

1.	The magnitude of the equatorial magnetic field due to a bar magnet of length 2 cm at a distance of 1lm from its mid-point is (magnetic moment of the bar magnet is 0.60 A m)A. `5.0xx10^(-5)` TB. `6.0xx10^(-8)` TC. `7.0xx10^(-7)` TD. `8.0xx10^(-8)` T
Answer» Correct Answer - B Magnetic field of equatorial point is `B_(E)=(mu_(0)m)/(4pir^(3))` Here, `=(mu_(0))/(4pi)=10^(-7), r` = 1 m and `m` = 0.60 A `m^(2)` `therefore" "B_(E)=(10^(-7)xx0.60)/((1)^(3))=6.0xx10^(-8)` T

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The magnitude of the equatorial magnetic field due to a bar magnet of length 2 cm at a distance of 1lm from its mid-point is (magnetic moment of the bar magnet is 0.60 A m)A. `5.0xx10^(-5)` TB. `6.0xx10^(-8)` TC. `7.0xx10^(-7)` TD. `8.0xx10^(-8)` T

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