1.

The major product of the following reaction is

Answer»




Solution :`CH_(3)O^(-)` is both a strong base as WELL as a strong nucleophile, thereofre both `S_(N_(2))` and `E_(2)` reactions are favourable. The given alkyl HALIDE is secondary `(2^(@))` in nature and `beta`-position is quite hindered. Therefore `E_(2)` is more favourable than `S_(N_(1))` pathway. since the polarity of the solvent `CH_(3)OH` is not quite high, `E_(1)` is also not favourable. under the conditions, `E_(2) `pathway is favourable.
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