1.

The mass defect of ""_(2)^(4)Heis 0.03 u. The binding energy per nucleon of helium (in MeV) is

Answer»

`27.93`
`6.9825`
`2.793`
`69.825`

SOLUTION :Mass DEFECT of `""_(2)^(4)He = 0.03 u`
Mass NUMBER = 4
Building ENERGY `= 0.03xx9.31=27.93`
Binding energy per nucleon `= (27.93)/(4)=6.9825`


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