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The mass of 1.2 cm^(3)of a certain sub- stance is 5.74g. caleulate its density with due regard to significant figures. |
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Answer» SOLUTION :Mass m =5.74 g, volume v, = 1.2 `cm^(3)` density d=`(m)/(v)= (5.74g)/(1.2cm^(3))` 5.74 has significant DIGITS and 1.2 has two significant digits . No need for rounding off. `:. D = (5.74)/(1.2)= 4.783333.` This is to be rounded off to two significant digits . The density of the GIVEN SUBSTANCE is 4.783 = `4.8 g cm^(-3)` |
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