1.

The mass of ._3^7Li is 0.042 amu less than the sum of masses of its constituents. The binding energy per nucleon is

Answer»

5.586 MeV
10.522 MeV
2.433 MeV
3.739 MeV

Solution :BINDING energy, `E_b` of `._3^7Li=Deltam` x 931 MeV
= 0.042 x 931 MeV
Binding energy per NUCLEON=`(0.042xx931)/7`
=5.586 MeV


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