1.

The mass of a ""_(7)^(3)Li nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of ""_(7)^(3)Li nucleus is nearly

Answer»

46 MeV
5.6 MeV
3.9 MeV
23 MeV

Solution :If `m = 1 u, C = 3 XX 10^(8) ms^(-1)` then,E = 931 MeV
`1 u = 931 MeV`
Binding energy `= 0.42 xx 931`
`= 39.10 MeV`
Binding energy PER nucleon = `(B.E)/(A) = (39.10)/(7) = 5.58 = 5.6 MeV`


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