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The mass of a nucleus ._(Z)^(A)X is less that the sum of the masses of (A-Z) number of neutrons and Z number of protons in the nucleus.The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass M can break into two light nuclei of masses m_(1) and m_(2) only if (m_(1)+m_(2)) lt M. Also two light nuclei of masses m_(3) and m_(4) can undergo complete fusion and form a heavy nucleus of mass M'. only if (m_(3)+m_(4)) gt M'. The masses of some neutral atoms are given in the table below: |{:(._(1)^(1)H ,1.007825u , ._(1)^(2)H,2.014102u,._(1)^(3)H,3.016050u,._(2)^(4)He,4.002603u),(._(3)^(6)Li,6.015123u,._(3)^(7)Li,7.016004u,._(30)^(70)Zn,69.925325u, ._(34)^(82)Se,81.916709u),(._(64)^(152)Gd,151.91980u,._(82)^(206)Pb,205.974455u,._(83)^(209)Bi,208.980388u,._(84)^(210)Po,209.982876u):}| The correct statement is: |
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Answer» The nucleus `._(3)^(6)Li` can emit an alpha particle `Deltam=][M_(Li)-M_(He)-M_(H^(3))]` `=[6.01513-4.002603-3.016050]` `= -1.003523u` `Delta m` is NEGATIVE so reaction is not possible. (B) `84^(Po^(210))rarr83^(Bi^(209))+1^(P^(1))` `Delta m` is negative so reaction is not possible. (c ) `1^(H^(2))rarr2^(He^(4))+3^(Li^(6))` `Deltam` is Positive so reaction is possible. (D) `30^(Zn^(70))+2^(Se^(82))rarr64^(Gd^(152))` `Deltam` is Positive so reaction is not possible. |
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