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The mass of a solid rectangular block of iron is 23.6g and its dimensions are `2.1cmxx1.2xx1.1cm`. Calculate the density of iron. |
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Answer» `V=2.1cmxx1.2cmxx1.1cm=2.772cm^3` `M=23.6g` `d=(M)/(V)=(23.6g)/(2.772cm^3)=8.514(g)/(cm^3)=8.514xx1000(kg)/(m^3)=8514(kg)/(m^3)` |
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