The mass of an electron 1/1840 part of mass of proton. When they are subjected to a uniform elecric field, they start accelerating(b) If they start from rest and have the same de Brogile wavelength of 1Å then determine the ratio of their kinetic energies.

The mass of an electron 1/1840 part of mass of proton. When they are s

1.	The mass of an electron 1/1840 part of mass of proton. When they are subjected to a uniform elecric field, they start accelerating(b) If they start from rest and have the same de Brogile wavelength of 1Å then determine the ratio of their kinetic energies.
Answer» SOLUTION :`lambda_e=h/sqrt(2m_ek_e), lambda_p=h/sqrt(2m_pk_p` SINCE these PARTICLES have same WAVELENGTH `h/sqrt(2m_ek_e)=h/sqrt(2m_pk_p )` `m_ek_e=m_pk_p ` ` k_e/k_p=m_P/m_e=1840`

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The mass of an electron 1/1840 part of mass of proton. When they are subjected to a uniform elecric field, they start accelerating(b) If they start from rest and have the same de Brogile wavelength of 1Å then determine the ratio of their kinetic energies.

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