1.

The mass of glucose that should be dissolved in 50 g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of urea in the same quantity of water is

Answer»

1 G
3 g
6 g
18 g

SOLUTION :`(p_(0)-p_(s))/(p_(s))=(w_(1)M_(2))/(w_(2)M_(1))`
To produce same lowering of vapour PRESSURE `((p_(0)-p_(s))/(p_(s)))` TERM will be same for both the cases (solvent is same).
`THEREFORE (w_(g)xx18)/(50xx180)=(w_(u)xx18)/(50xx60)`
(`w_(g)=`weight of glucose, `w_(u)=`weight of urea)
or,`(w_(g)xx18)/(50xx180)=(1xx18)/(50xx60)`or,`w_(g)=3`.


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