1.

The mass of one litre sample of ozonised oxygen at `NTP` was found to be `1.5 g`. When `100 mL` of this mixture at `NTP` were treated with terpentine oil, the volume was reduced to `90 mL`. Hence calculate the molecular mass of ozone. (Terpentine oil absorbs ozone)

Answer» Volume of ozone=Volume absorbed in turpentine oil =10mL
Volume of oxygen=90mL
Mass of 100mL mixture `=(10)/(22400)xxM+(90)/(22400)xx32`
On solving, we get M=48
Molecular mass of ozone=48


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