1.

The mass of P4O10 that will be obtained from the reaction of 1.33 gram of P4 and 5.07 of oxygen is

Answer»

 3.05 gram



Balanced chemical EQUATION:
P4 + 5O2 --------> P4O10
1 mol 5 mol 1 mol
124g 160g 284g
Here limiting REAGENT is P4.
So, 124g of P4 produce P4O10 = 284g
Therefore,
1.33g of P4 produce P4O10 = (284/124)*1.33
= 3.05g



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