1.

The mass of proton is 1.0073 u and that of neutron is 1.0087 u ( u=atomic mass unit ). The binding energy of ._2^4He , if mass of ._2^4Heis 4.0015 u is

Answer»

0.0305 erg
0.0305 J
28.4 MeV
0.061 U

Solution :`Deltam=2m_p + 2m_n -m(._2^4He)`
=2 x 1.0073 + 2 x 1.0087 - 4.0015 =0.0305 u
Binding ENERGY = 0.0305 x 931 MeV = 28.4 MeV


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