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InterviewSolution
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The mass of the Earth is `6 xx 10^(24)` kg and its radius is 6400 km. Find the acceleration due to gravity on the surface of the Earth. |
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Answer» Given Mass of the Earth, `M = 6 xx 10^(24) kg` Radius of the Earth, `R = 6400 km = 64 xx 10^(5) m` Universal gravitational constant, `G = 6.67 xx 10^(-11) N m^(2) kg^(-2)` Acceleration due to gravity on the surface of the Earth, `g = (GM)/(R^(2))` `" "g = (GM)/(r^(2))=(6.67 xx 10^(-11) xx 6 xx 20^(24))/((64 xx 10^(5)))=9.77 m s^(-2)` |
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